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Anonymous Posted on Feb 08, 2014

Fluke 1653 error1 - Televison & Video

1 Answer

Vuk B

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  • Master 717 Answers
  • Posted on Dec 03, 2014
Vuk B
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Related Questions:

0helpful
2answers

Fluke 115 True RMS Digital Multimeter. I have an EEpr error problem.

Question edited for clarity.
Question moved from Computers to Fluke.

EEPr Err Internal error. The Meter must be repaired before it will operate.

Page 6

https://assets.fluke.com/manuals/115c117cumeng0100.pdf

More here, but you probably need to return it for repair.

https://www.google.com/search?q=Fluke+115+eepr+error

..
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1answer

Machine error1 broke needle then machine come error1 can i override

Look for Error 1 in the troubleshooting section of your owner's manual or search for:

Make Model Error 1
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1answer

I am looking for a user manual for a Bissell 1653-6 portable little green machine. Not sure how to operate this machine.

Hello, this is Ava with Think Crucial.

You may find the User's Manual for your Bissell model by clicking the link below.

Bissell Little Green 1653 4 User Manual

You can purchase a wide variety of high quality Bissell replacement parts for your Bissell vacuum direct from Think Crucial with free shipping and an exclusive 10% coupon for Fixya.com readers, use code: FIXYA10

https://www.thinkcrucial.com/collections/vendors?q=Bissell

I hope this was helpful.

Ava B.
Think Crucial Customer Care
http://www.thinkcrucial.com/
Sep 05, 2011 • Vacuums
0helpful
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0helpful
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Need help in Special Formatting Number

Here is one solution. You might consider adding more robust error handling.
if the decimal numbers passed to the div function are multiples i will be a non-zero number of that multiple otherwise i will be zero.

Dim i As Integer
i = div(12, 0)
If i = 0 Then
'not multiple
' do this
Else
' is multiple
' do something else
End If


Function div(ByVal numerator As Object, ByVal denominator As Object) As Integer
dim n , d decimal
Dim result As Decimal
Dim remainder As Decimal

If IsNumber(numerator) Is True _
And IsNumber(denominator) Is True Then
If numerator <> 0 Then
n = numerator
d = denominator
Else
GoTo error1
End If
Else
GoTo error1
End If
result = Decimal.divide(n, d)
remainder = Decimal.remainder(n, d)
If remainder = 0 Then
div = result
Else
div = 0
End If

Exit Function
error1:
msgbox("Numbers must be non-zero numerics", , "Multiple check error")
div = 0
End Function

End Function
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