Questions & Answers for: 2x 3

...67 A. 3X+(-1.67)=2 3X-1.67=2 3X=2+1.67 3X=3.67 X=3.67/3 X=1.22 (3x-2y)2 = 2x=4 3x+y=2;2x-y sol'n: 3x+y=2 y=2x-3 3x+2x-3=2 5x\5=2+3\5 x=1 3(1)+y=2 3+y=2 y=2-3 y=-1 ans.x=1;y=-1 ...

...In seven years, the product of their ages would be 5 more than the product of their ages 5 years ago. How old are they now? 4x+7=2(x-3) 4x+7=2x-6 4x-2x=-7-6 2x = -13 2x/2 = -13/2 x = -6.5 ...

3*10 - 13 = 17) Let x=Ruel's age now, and 2x=Edwin's age now. 2x+3=3(x+3)-13 2x+3=3x+9-13 2x+3=3x-4 2x+7=3x 7=x If you are going to post these, the least you could do is rate them as Fixya. :-) Thanks

...2x+3 Now, your problem looks like this: 2(2x-1)(2x+1) = (2x+1)(2x+3) + 7 2(4x^2-1) = 4x^2+6x+2x+3 + 7 8x^2-2 = 4x^2+8x+10 4x^2-8x-12 = 0 4(x^2-2x-3) = 0 x^2-2x-3 = 0 The solutions for this quadratic ...

...derivative of 29/2*[cos(X)-cos(3X)] which is 29/2*[-si(X) +3*sin(3X)] The challenge for you is to prove that the two forms are equivalent 29*2*cos(2X)*sin(X)+29*sin(2X)*cos(X)=29/2*[-si(X)

2x-3)=0 4x-(2x-3)=0 =>4x-2x+3=0 ; (after the bracket's oepned and multiplied by - [minus]) =>2x+3=0 ; taken x as common and 4-2=2 i.e. x(4-2) = 2x =>2x=-3 ; +3's moved on the right-hand side,

Pls solve 2x-3/=3 2x-3=3 2x=6 x = 3

...3 1) 2x + 5y = 7 2) 3x + 6y = 3 I'm going to use the method of elimination to solve for x and y. Multiply 1) by 3 and 2) by 2 to allow the x's to be eliminated. 1) 6x + 15y = 21 2) 6x + 12y = 6 Now ...

3 2x = 8 x = 4 so the perimeter is 3 times either expression above 3 * (8 + 5) = 39 . Since side a = side b = side c, 4x - 3 = 2x + 5 4x - 2x = 5 + 3 2x = 8 x = 8 / 2 = 4 Therefore each side = 2*4 + 5

2x+3\4)=0 easy: 2log(x) + log(3/4) - log(2x + 3/4) = 0 log(x^2) + log(3/4) = log(2x + 3/4) log(3/4*x^2) = log(2x + 3/4) 3/4*x^2 = 2x + 3/4 multiply equation by 4: 3x^2 = 8x + 3 3x^2 - 8x - 3 = 0 solve