Questions & Answers for: 4x 1

1/cot^4X + 1/cot^2X sec^4X- sec^2X = 1/cot^4X + 1/cot^2X RHS 1/cot^4X + 1/cot^2X =1/(Cos^4X/Sin^4X) + 1/(Cos^2X/Sin^2X) =Sin^4X/Cos^4X + Sin^2X/Cos^2X =Sin^4X/Cos^4X + Cos^2X.Sin^2X/Cos^4X =Sin^2X/Cos

4x+8y=20 -4x+2y=-30 4x+8y=20 || /4 x+2y=5 x=5-2y -4x+2y=-30 || /2 -2x+y=-15 -2(5-2y)+y=-15 -10+4y+y=-15 5y=-5 y=-1 x=5-2y || y=-1 x=5-2(-1) x=5+2 x=7

...While result is correct, I can also open the parentheses y= -4x/3 +6/3 y= -(4/3)*x +2. Hope it helps. Type the following into your calculator: solve(4x+3y=6,y) 13 1/2 - 10 1/12 - 3 2/6 + 4 ...

...1) + (52-x)(5) = 120 x + 260 - 5x = 120 260 - 4x = 120 260 - 4x + 4x = 120 + 4x 260 = 120 + 4x 260 - 120 = 120 + 4x - 120 140 = 4x 35 = x = Number of pennies 52 - 35 = 17 = Number of nickels Verify: ...

... 2 has been moved to the right-hand side and divided with -3 i.e 1/2 multiplied by -3 = -3/2 Hence, x = -3/2 Good luck. Thanks for using FixYa. 4x-(2x-3)=0 4x=2x-3 4x-2x=-3 2x=-3 x=-3/2 =-1.5 or -1 ...

...1*(x-3)]= (x+2)*(x^2-3x-x+3)= (x+2)(x^2-4x+3)= x*(x^2-4x+3)+2*(x^2-4x+3)= x^3-4x^2+3x+2x^2-8x+6= x^3-2x^2-5x+6x^3-2x^2-5x+6 is polynomial with roots -2, 1, 3. You can see this polynomial in following ...

...{7(2)2+[(3-2)-4x(3)]2 if you mean {7(2)2+[(3-2)-4x(3)]2} or 7(2)2+[(3-2)-4x(3)]2 {28+[(1)-12]2} {28+[-12]2} {28+-24} =4 or if it was 4x not 4 times {7(2)2+[(3-2)-4x(3)]2} 28+[(1)-12x]2 28+-24x ...

1)=4x help solve x equals 1 First multiply the numbers outside the parentheses by what is inside the parentheses, which results in: 6 - 2x + 3x - 3 = 4x then combine what you can: 6 - 3 = 3, -2x + 3x

what is the inverse of 3x/4x-1 If your question is the inverse of 3x / (4x - 1) then (4x - 1) / 3x If you meant (3x / 4x) - 1 then - 4

4x)=9 (-1) (-1)(7-4x) = 9 (-1) multiply both sides by -1 to get rid of the negative sign 7-4x=-9 7-4x-7=-9-7 subtract 7 from both sides -4x = -16 -4x = -16 ----- ----- divide both sides by -4 to get x